qaunts

mandalia05
Posts: 1
Joined: Fri Jun 30, 2017 10:28 am

qaunts

Postby mandalia05 » Sat Aug 26, 2017 7:01 pm

The joint probability distribution of random variables X and Y is given by
f(x, y) = k × x × y for x = 1, 2, 3, y = 1, 2, 3, and k is a positive constant.
What is the probability that X + Y will exceed 5?
a. 1/9
b. 1/4
c. 1/36
d. Cannot be determined.

having a problem with this question.

edupristine
Finance Junkie
Posts: 871
Joined: Wed Apr 09, 2014 6:28 am

Re: qaunts

Postby edupristine » Fri Oct 06, 2017 10:01 am

We have given that X and Y both can take values from 1,2,3

So total number of co-ordinates (x,y) possible = 3 X 3 = 9.

{(1,1) (1,2) (1,3) (2,1) (2,2)(2,3) (3,1)(3,2)(3,3)}

Out of these 9, only 1 co-ordinate (x,y)=(3,3) is such that X+Y exceeds 5.

Therefore the required probability = 1/9


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